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Reliance Jio & Google Working Together to Launch $30 4G Smartphone & Smart TV Software Will It Affect LYF Brand, VoLTE Feature Phones, And Android One? Reliance Jio is now planning to  launch affordable 4G smartphones in collaboration with Google . The company has already started working with  Google for developing a competitively priced 4G smartphone and software for smart TV services. As reported by Business Line, these 4G smartphones will  work exclusively on Jio 4G  network. This partnership with Google will not only help Jio get a  wider market reach  for its 4G smartphones but will also ensure  tight integration of Jio apps  into the Android platform. “I think two big things, one is from our side — we are committed to making even cheaper smartphones. […] The right price point for smartphones in India is $30, and pursuing high-quality smartphones at the price point will unlock it even more,” said Google CEO, Sundar Pichai, during his India visit. Little di

Reliance Jio Offers 100% Cashback For Prime Membership; Upto 120 GB Free

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Reliance Jio Offers 100% Cashback For Prime Membership; Upto 120 GB Free  Prime Membership Can Now Be 100% Free Use Jio Money app to purchase Jio Prime membership costing Rs 99. Under their new offer, you will get Rs 50 cashback on Jio Money. Then, use Jio Money again to recharge Rs 303 or Rs 499 for one month. Under the existing offer, you will again get Rs 50 cashback on Jio Money. At this moment, you have already bought Jio Prime Membership by paying Rs 99; recharged your Jio number for Rs 303 or Rs 499 for a month, and received cashback of Rs 100 on Jio Money. Hence, basically, you are getting Jio Prime membership for free. All you need to pay is monthly recharge of Rs 303 or Rs 499 Up to 120 GB Free On Annual Recharges The period post-March 31st would be the real litmus test for Mukesh Ambani’s Jio because, after that day, Jio would be no longer free. The number of Prime’s paid customer base shall determine Jio’s true impact, and the company has left no

How To Get Jio Prime Membership @ Rs 49 – Mobikwik

**How To Get   Jio Prime Membership @ Rs 49 – with Mobikwik ????** Mobikwik is offering free SuperCash to its users. You can get Jio Prime Membership @ Rs 49 only. Mobikwik is giving Rs 5o cashback called # SuperCash to its users who buy Jio prime membership through Mobikwik. Jio Prime Membersip actually costs Rs 99. You have to recharge Rs 99 to  become Jio Prime member  but using this offer by Mobikwik you get some benefits. STEPS:- 1)  DOWNLOAD   Mobikwik   FROM PLAYSTORE 2) REFER CODE "UNVQFU" FOR CASHBACK 3) ENTER YOUR MOBILE NUMBER 3) PAY WITH     Mobikwik  FOR JIO Prime Membership WITH FOLLOWING PROMO      CODE If you are a Mobikwik user, you will get Rs 20 SuperCash on Jio prime subscription of Rs 99. ****To get Rs 20 SuperCash use code:  PRIME If you are new to Mobikwik, you get flat 50 SuperCash on Jio Prime Membership Subscription. It means you are paying only Rs 49 for Jio Prime Membership worth Rs 99. ****To get Rs 49 Sup

euclidean Algorithm to find GCD

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AIM Implement euclidean Algorithm to find GCD of two numbers. CODE #include <stdio.h> int gcd_algorithm(int x, int y) {     if (y == 0) {         return x;     } else if (x >= y && y > 0) {         return gcd_algorithm(y, (x % y));     } } int main(void) {     int num1, num2, gcd;     printf("\nEnter two numbers to find gcd using Euclidean algorithm: ");     scanf("%d%d", &num1, &num2);     gcd = gcd_algorithm(num1, num2);     if (gcd)         printf("\nThe GCD of %d and %d is %d\n", num1, num2, gcd);     else         printf("\nInvalid input!!!\n");     return 0; } OUTPUT

vigenere cipher substitution technique

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AIM: To implement a program for encryption and decryption using vigenere cipher substitution technique Code: #include<bits/stdc++.h> using namespace std; string generateKey(string str, string key) {     int x = str.size();     for (int i = 0; ; i++)     {         if (x == i)             i = 0;         if (key.size() == str.size())             break;         key.push_back(key[i]);     }     return key; } string cipherText(string str, string key) {     string cipher_text;     for (int i = 0; i < str.size(); i++)     {         int x = (str[i] + key[i]) %26;         x += 'A';         cipher_text.push_back(x);     }     return cipher_text; } string originalText(string cipher_text, string key) {     string orig_text;     for (int i = 0 ; i < cipher_text.size(); i++)     {         // converting in range 0-25         int x = (cipher_text[i] - key[i] + 26) %26;         x += 'A';         orig_text.push_back(x);     }     re

Hill cipher substitution

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AIM:  To implement a program to encrypt and decrypt using the Hill cipher substitution technique. CODE #include<iostream> #include<cstring> using namespace std; int main(){     int i,j,k,matrix[2][2],inverse[2][2],det,detinv;     char str[20],encrypted[20],decrypted[20],key[4];     cout<<"Enter key : ";     cin>>key;     cin.ignore();     for(i=0;i<2;i++){         for(j=0;j<2;j++){             matrix[i][j]=key[i*2+j]-97;         }     }     cout<<"Encryption Matrix : "<<endl;     for(i=0;i<2;i++){         for(j=0;j<2;j++){             cout<<matrix[i][j]<<"\t";         }         cout<<endl;     }     det=(676+matrix[0][0]*matrix[1][1]-matrix[0][1]*matrix[1][0])%26;     if(det==0||det%2==0||det%13==0){         cout<<"Invalid Key";         return -1;     }     cout<<"Determinant : "<<det<<endl;     i=1;     while(1

Cipher substitution technique

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AIM :  To implement a program to encrypt a plain text and decrypt a cipher text using play fair Cipher substitution technique. CODE  #include<stdio.h> #include<conio.h> #include<string.h> #include<ctype.h> #define MX 5 void playfair(char ch1,char ch2, char key[MX][MX]) {  int i,j,w,x,y,z;  FILE *out;  if((out=fopen("cipher.txt","a+"))==NULL)   {    printf("File Currupted.");   }  for(i=0;i<MX;i++)  {   for(j=0;j<MX;j++)   {    if(ch1==key[i][j])    {     w=i;     x=j;    }    else if(ch2==key[i][j])    {     y=i;     z=j;    }   }  }  if(w==y)  {   x=(x+1)%5;z=(z+1)%5;   printf("%c%c",key[w][x],key[y][z]);   fprintf(out, "%c%c",key[w][x],key[y][z]);  }  else if(x==z)  {   w=(w+1)%5;y=(y+1)%5;   printf("%c%c",key[w][x],key[y][z]);   fprintf(out, "%c%c",key[w][x],key[y][z]);  }  else  {   printf("%c%c",key[w][z],key[y][x]);   fp